The binding energy per nucleon for deuteron `_(1)H^(2)` and helium `_(2)He^(4)` are 1.1 MeV and 7.0 Mev, respectively. The energy released when two deuterons fuse nucleus is

Options

A. `36.2 MeV`
B. `23.6 MeV`
C. `47.2 MeV`
D. `11.8 MeV`

Answer

B

Explanation

The nuclear reaction is,
`"_(1)H^(2)+_(1)H^(2)rarr_(2)He^(4)+O`
Total binding energy of helium nulceus
`=4xx7=28 MeV`
Total binding energy of each deuteron
`=2xx1.1=2.2 MeV`
Hence, energy released when teo deuteron fuse to from helium,
`=28-2xx2.2=28-4.4=23.6 MeV`