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An electric dipole of moment mu of 400 m...

An electric dipole of moment `mu` of 400 `mu`C m is placed in a transverse electric field (E) of 50 `Vm^(-1)` at an angle of `30^(@)` to E. Then, a torque of

A

`10^(-2)` Nm acts along the direction E

B

`10^(-3)` Nm acts along the direction `mu`

C

`10^(-5)` Nm acts normal to both E and `mu`

D

`10^(-3)` Nm acts along the direction E

Text Solution

Verified by Experts

The correct Answer is:
B
Given, `P=400muC=400xx10^(-6)C`
`E=50Vm^(-1)`
`theta=30^(@)`
We know that, torque acting on an electric dipole,
`pi=PE"sin"theta`
where, P = dipole moment
`=400xx10^(-6)xx50xx"sin"30^(@)`
`=400xx10^(-6)xx50xx1/(2)`
`=200xx50xx10^(-6)=10^(-2)N-m`
This torque will act normal to both `Eandmu`.
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