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If a body of moment of inertia 2kg m^(2)...

If a body of moment of inertia `2kg m^(2)` revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is

A

`2pi`

B

`4pi`

C

`6pi`

D

`8pi`

Text Solution

Verified by Experts

The correct Answer is:
D
Given, Moment of inertia of body (l) `= 2 kg m^(2)`
Rotation of body in one second (f) = 2
We know that,
Angular momentum (L) = `l omega`
`L = 2 xx 2pi f`
`L = 2 xx 2pi (2)`
`L = 8 pi J//s`
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