A torque of 1 N-m is applied to a wheel which is at rest. After 2 second the angular momentum in `kg-m^(2)/s` is

Options

A. 0.5
B. 1
C. 2
D. 4

Answer

C

Explanation

As `tau=I alpha`
So `alpha=(tau)/(I)`
and l=Iw
`=I(tau)/(I) triangle t=tau triangle t`
`=2 kgm^(2)s^(-1)`