Variable Acceleration

HW-2||Questions on Variable||Acceleration||Graphs

In the diagram shown, the displacement of particles is given as a function of time. The particle a is moving under constant velocity of 9 m//s . The particle B is moving under variable acceleration. From time t=0 s to t=6 s . The average velocity of the particle B will be equal to :-

A particles moves along a circle of a fixed radius with a variable acceleration given by a_(n) = kt^(n), where k is a constant and t time. If the power 'P' delivered by all forces acting on it be plotted against time 't' on a log-log scale, the slope of the straight line obtained is 2 as shown in Figure below. The value of n is:

The equation of one dimensional motion of the particle is described in column I. At t=0 , particle is at origin and at rest. Match the column I with the statement in Column II. {:(,"Column I",,,"Column II"),((A),x=(3t^(2)+2)m,,(p),"Velocity of particle at t=1s is "8 m//s),((B),v=8t m//s,,(q),"Particle moves with uniform acceleration"),((C),a=16 t,,(r),"Particle moves with variable acceleration"),((D),v=6t-3t^(2),,(s),"Particle will change its direction some time"):}

Write a short note on acceleration, average acceleration, variable accleration and instantaneous acceleration Also show how instantaneous acceleration is related to average acceleration.

A body is moving with variable acceleartion (a) along a straight line. The average acceleration of body in time interval t_(1)" to "t_(2) is :-

Angular Acceleration|Tangential Acceleration|Radial Acceleration|Questions|Relations Among Angular Variables

Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of a particle after 10 seconds starting from rest with a uniform acceleration of 2m//s^(2)

Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of the particle when its velocity becomes 10m//s if acceleration is 5m//s^(2) all through -

Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the velocity of the particle after 10 seconds if its acceleration is zero in interval (0 to 10s)-