Distance of the Plane `2x-y+2z+3=0` from `(3,2,-1)` is

Distance of a plane 2x+y+2z+5=0 from a point (2,1,0) is

find distance of the plane 2x-y+3z=4 from point (1,0,-2)

The distance of the plane 6x-3y+2z-14=0 from the origin is

Find the distance of the plane 2x-3y+4z-6=0 from the origin.

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x-2y+z=0 and x-y+2z=4. The distance of the plane from the point (0, 2, 2) is

The square of the distance of the point of intersection of the line and the plane (x-1)/(2)=(y-2)/(3)=(z+1)/(6) and the plane 2x-y+z=6 from the point (- 1, -1, 2) is_________

If L_(1) is the line of intersection of the planes 2x-2y+3x-2=0x-y+z+1=0 and L_(2) is the line of the intersection of the planes x+2y-z-3=0 3x - y+2z-1=0 then the distance of the origin from the plane containing the lines L_(1) and L_(2) is