Distance of the plane `2x-y+2z+3=0` from `(3, 2 ,-1)` is
`a. 5/3 b. 2/1
c. 3/13 d. 13/3`

Distance of the plane 4x+5y+3z = 6 from the point (-2,-1,1) is (3^a+b)/(25sqrt(2)) , then (b-a) is.

The image of the point (1, 3, 4) in the plane 2x-y+z+3=0 is (3,\ 5,\ 2) b. (-3,5,\ 2) c. (3,\ 5,\ -2) d. (3,\ -5,\ 2)

Distance of point (1,3) from the line 2x-3y+9=0 along x-y+1=0

The distance of the point (2,1,-1) from the plane x-2y+4z=9 is (A) sqrt(13)/21 (B) 13/21 (C) 13/sqrt(21) (D) sqrt(13/21)

The distance of the point (2,1,-1) from the plane x-2y+4z=9 is (A) sqrt(13)/21 (B) 13/21 (C) 13/sqrt(21) (D) sqrt(13/21)

The plane ax+by+cz=105 contain the lines 2x-y+z=3and3x+y+z=5 . If point (2 ,1, -1) is at a distance of (1)/(sqrt(6)) from the plane , then a+b+c=

Find the image of the point : (i) (2,-3,2) in the plane 2x + y - 3z = 10 (ii) (1,2,3) in the plane x + 2y + 4z = 38 (iii) (2,-1,3) in the plane 3x - 2y - z = 9.

The number of solutions of the system of equations: 2x+y-z=7,\ \ x-3y+2z=1,\ \ x+4y-3z=5 is (a) 3 (b) 2 (c) 1 (d) 0

If theta is the angel between the planes 2x-y+z-1=0 and x-2y+z+2=0 then costheta= (A) 2/3 (B) 3/4 (C) 4/5 (D) 5/6

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to