The intensity of gamma radiation from a given source is `I`
On passing through `36 mm` of lead , it is reduced to `(1)/(8)` . The thickness of lead which will reduce the intensity to `(1)/(2)` will be

The intensity of gamma radiation from a given source is 1 On passing through 36 mm of lead , it is reduced to (1)/(8) . The thickness of lead which will redace the intensity to (1)/(2) will be

The intensity of gamma radiation form a given source is I. On passing through 27 mm of lead, it is reduced to I//8 . The thickness of lead which will reduce the intesity to I//2 will be:

The inteisity of gamma radiation from a given source is I_(0) . On passing throug 37.5 mm of lead it is reduced to I_(0) // 8. the thickness of lead which will reduce It to I_(0) //2 is -

The intensity of gamma - radiation from a given source is I. On passing through 36 mm of lead, it is reduced to I//8 . Assuming that the intensity in trasmitted radiation varies expontially with the thickness of the material, then the thickness of lead, which will reduce the intensity to I//2 will be

The intensity of gamma - from a source (I_(0)) reduces to I_(0)//8 after passing through 48 mm thick sheet of lead. The thicness of the sheet for obtaining intensity equal to I_(0) / 2 will be-

The intensity of X–rays of wavelength 0.5Å reduces to one fourth on passing through 3.5 mm. Thickness of a metal foil. The coefficient of absorption of metal will be–

The intensity of a sound wave gets reduced by 20% on passing through a slab. The reduction intensity on passage through two such consecutive slabs

The intensity of sound from a point source is 1.0 xx 10^-8 Wm^-2 , at a distance of 5.0 m from the source. What will be the intensity at a distance of 25 m from the source ?