A particle moves in such a way that its acceleration a= - bx, where x is its displacement from the mean position and b is a constant. The period of its oscillation is

A particle moves such that its acceleration a is given by a = -bx , where x is the displacement from equilibrium positionand is a constant. The period of oscillation is

A particle moves such that its acceleration ‘a’ is given by a = – zx where x is the displacement from equilibrium position and z is constant. The period of oscillation is

The equation of motion of a particle executing S.H.M. is a = - bx , where a is the acceleration of the particle, x is the displacement from the mean position and b is a constant. What is the time period of the particle ?

Acceleration of a particle in SHM at displacement x=10 cm (from the mean position is a =-2.5 cm//s^(2) ). Find time period of oscillations.

A particle moves such that its acceleration is given by a =- beta (x-2) Here beta is positive constant and x is the position form origin. Time period of oscillation is

A particle is performing SHM aong x-axis,such that its velocity is v_1 when its displacement from mean position is x_1 and v_2 when its displacement from mean position is x_2 .Time period of oscillation is

The equation of SHM of a particle is given as 2(d^(2)x)/(dt^(2))+32x=0 where x is the displacement from the mean position. The period of its oscillation ( in seconds) is -

A particle in linear SHM has speeds 4 cm/s and 3 cm/s when its displacements from the mean position are 3 cm and 4 cm , respectively. Find its period of oscillation.