In the arrangement shown in figure, coefficient of friction between the two blocks is `mu=1//2`. The force of friction acting between

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

For the arrangement shown in the figure the coefficient of friction between the two blocks is mu . If both the blocks are identical and moving ,then the acceleration of each block is

Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

Two blocks A and B are lying on the table as shown in the figure. The coefficient of friciton between block A and block B is mu . The coefficient of friction between block B and ground also mu . An external force F is applied in the direction shown. The maximum value of the force F that can be applied without moving the blocks.

Two blocks of masses 'm' and and 'M' are arranged as shown in the The coefficient of friction between the two blocks is 'mu' , where as between the lower block and the horizontal surface is zero. Find the force 'F' to be applied on the upper block for the system to be under equilibrium ? .

A force of 100N is applied on a block of mass 3kg as shown in the figure. The coefficient of friction between the surface and the block is mu=(1)/(sqrt(3) . The friction force acting on the bock is.

A block of mass m=1 kg has a speed v = 4 m//s at theta = 60^(@) on a circular track of radius R = 2 m as shown in figure. Size of the block is negligible. Coefficient of friction between block and the track is mu = 0.5 . The force of friction between the two is

In the arrangement shown in the figure, friction exists only between the two blocks, A and B. The coefficient of static friction mu_(s)=0.6 and coefficient of kinetic friction mu_(k)=0.4 , the masses of the blocks A and B are m_(1)=20 kg and m_(2)=30kg , respectively. Find the acceleration (in ms^(-2) ) of m_(1) , if a force F=150N is applied, as shown in the figure. [Assume that string and pulleys are massless]