If `sin^2 theta = 1+cos^6 theta` then number of values of `theta` in range `(0, 2pi)` is

If the points (-2, 0), (-1,(1)/(sqrt(3))) and (cos theta, sin theta) are collinear, then the number of value of theta in [0, 2pi] is

If (cos^(3) theta )/( (1- sin theta ))+( sin^(3) theta )/( (1+ cos theta ))=1+ cos theta , then number of possible values of theta is ( where theta in [0,2pi] )

If the system of linear equations {:((cos theta)x + (sin theta) y + cos theta=0),((sin theta)x+(cos theta)y + sin theta=0),((cos theta)x + (sin theta)y -cos theta=0):} is consistent , then the number of possible values of theta, theta in [0,2pi] is :

Solve sin^2 theta- cos theta =1/4 " for " theta and write the value of theta in the interval 0 le theta le 2 pi

If 2sin^(2)theta=3cos theta, where 0<=theta<=2 pi, then find the value of theta

If sin^(8)theta+cos^(8)theta-1=0 then what is the value of cos^(2)theta sin^(2)theta

The value of sin^6 theta+ cos^6 theta + 3 cos^2 theta sin^2 theta is