A body is thrown up with a velocity `40 ms ^(-1).` At same time another body is dropped from a height 40 m. Their relative acceleration after `1.3` seconds is

[" A body is thrown up with a "],[" velocity "40ms^(-1)" .At same time "],[" another body is dropped from "],[" a height "40m" .Their relative "],[" acceleration after "1.3],[" seconds is "]

One body is thrown up with velocity of 34.6ms 1. Another body is dropped from a height of 50m. Relative acceleration between the two bodies is

One body is thrown up with velocity of 34.6ms Another body is dropped from a height of 50m. Relative acceleration between the two bodies is -A) 9.8 ms-2 B) 19.6 ms-2 C) Zero D) 4.9 ms-2

A body A is thrown vertically upwards with initial velocity v_(1) . Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the bodies begin to move simultaneously.

A body is thrown up in a lift with a velocity 5ms^(-1) relative to the lift and the time of flight is found to be 0.8 s. The acceleration with which the lift is moving up is (g=10ms^(-2))

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

[" A body is thrown vertically "],[" upwards with "39.2m/sec],[" velocity at the same time "],[" another body is dropped from "],[" 100m height.After how long "],[" the bodies acquires same "],[" velocity."]

A body A is thrown up vertically from the ground with velocity V_(0) and another body B is simultaneously dropped from a height H. They meet simultaneously dropped from a height H. They meet at a height (H)/(2) if V_(0) is equal to

A body is projected up with a velocity 50 ms^(-1) after one second if acceleration due to gravity disappears then body

A body is dropped from a height of 40 m from the surface of the Earth. Its final velocity is 28 m s^(-1) . What would be the final velocity of the body, if it is dropped from the same height on another planet where the acceleration due to gravity is 2.5 m s^(-2) . Assume atmospheric conditions to be similar. (Take earth = 10 m s^(-2) )