The solutiion of `(x,y,z)` the equation `[(-1,0,1),(-1,1,0),(0,-1,1)][(x),(y),(z)]=[(1),(1),(2)]` is `(x,y,z)`

If [(1,2,-3),(0,4,5),(0,0,1)][(x),(y),(z)]=[(1),(1),(1)] , then (x, y, z) is equal to

If [(1,0,0 ), (0,-1,0), (0,0, -1)][(x),(y),( z)]=[(1),(0),(1)] , find x ,\ y\ a n d\ z .

The solution of the equation [[1,0 ,1],[-1,1 ,0],[0 ,-1,1]][[x],[ y] ,[z]]=[[1],[ 1],[ 2]] is

If [(1 ,0, 0) ,(0 ,1, 0),( 0 ,0 ,1)][(x),( y),( z)]=[(1),(-1),( 0)] , find x ,\ y\ a n d\ z .

If [(1, 0 ,0 ),(0,y,0),( 0, 0, 1)][(x),(-1),(z)]=[(1),( 0),( 1)] , find x ,\ y\ a n d\ z .

If [{:(1,1,1),(1,-2,-2),(1,3,1):}][{:(x),(y),(z):}]=[{:(0),(3),(4):}] , then [{:(x),(y),(z):}] is equal to

If [[1,0,0],[0,1,0],[0,0,1]][[x],[y],[z]]=[[1],[-1],[0]] then value of (x+y+z)is

If [{:(,x-y,1,z),(,2x-y,0,w):}]=[{:(,-1,1,4),(,0,0,5):}], "find x,y,z,w"

Choose the correct answer in questions 17 to 19: If x, y, z are nonzero real numbers then the inverse of metrix A=[{:(x,0,0),(0,y,0),(0,0,z):}] is : (a) [{:(x^(-1),0,0),(0,y^(1),0),(0,0,z^(1)):}] (b) xyz[{:(x^(-1),0,0),(0,y^(1),0),(0,0,z^(1)):}] ( c) 1/(xyz)[{:(x,0,0),(0,y,0),(0,0,z):}] (d) 1/(xyz)[{:(1,0,0),(0,1,0),(0,0,1):}]

STATEMENT-1 : The centroid of a tetrahedron with vertices (0, 0,0), (4, 0, 0), (0, -8, 0), (0, 0, 12)is (1, -2, 3). and STATEMENT-2 : The centroid of a triangle with vertices (x_(1), y_(1), z_(1)), (x_(2), y_(2), z_(2)) and (x_(3), y_(3), z_(3)) is ((x_(1)+x_(2)+x_(3))/3, (y_(1)+y_(2)+y_(3))/3, (z_(1)+z_(2)+z_(3))/3)