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12 g carbon combines with 64 g sulphur t...

12 g carbon combines with 64 g sulphur to form `CS_2`. 12 g carbon also combines with 32 g oxygen to form `CO_2`. 10 g sulphur combines with 10 g oxygen to form `SO_2` These data illustrate the

A

law of multiple proportions

B

law of definite proportions

C

law of reciprocal proportions

D

law of gaseous volumes.

Text Solution

Verified by Experts

The correct Answer is:
C
Weight of sulphur combining with 12 g of carbon=64 g Weight of oxygen combining with 12 g of carbon = 32 g Weight ratio of sulphur and oxygen = S:0= 2:1 10 g of sulphur combines with 10 g of oxygen to form `SO_2`.
` therefore `Weight ratio of S and O in `SO_2, S:O=1:1` Hence, it illustrates law of reciprocal proportions.
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