Home
Class 11
CHEMISTRY
3 g of a hydrocarbon on combustion with ...

3 g of a hydrocarbon on combustion with excess of oxygen produces 8.8 g of `CO_2` and 5.4 g of `H_2 O`. The data illustrates the law of

A

conservation of mass

B

multiple proportions

C

constant proportions

D

reciprocal proportions.

Text Solution

Verified by Experts

The correct Answer is:
A
Amount of carbon in 8.8 g `CO_2 = 12 xx` number of moles of `CO_2 4-(12 xx 8.8 )/(44) = 2.4 g `
Amount of hydrogen in 5.4 g `H_2 O`
`= 2 xx ` number of moles of `H_2 O = ( 2 xx 5.4 )/(18 ) =0.6 g`
Weight of carbon + weight of hydrogen
`= 2.4 +0.6 =3.0 g ` =weight of hydrocarbon.
Hence, it illustrates law of conservation of mass.
Promotional Banner

Similar Questions

Explore conceptually related problems

3g of a hydrocarbons on combusion in excess of oxygen produces 8.8g of CO_(2) and 5.4g of H_(2)O . The data illustrates the law of:

6g of a hydrocarbon on combustion in excess of oxygen produces 17.6g of CO_(2) and 10.8g of H_(2)O . The data illustrates the law of :

1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of CO_(2) and 2.7 g of H_(2)O , the data illustrates

25 g hydrocarbon of burning with excess of air produces 88 g CO_(2) and 9g water, mass of C and H in the hydrocarbon is

0.44 g of a hydrocarbon on complete combustion with oxygen gave 1.8 g of water and 0.88 g of carbon dioxide. Show that these result are in agreement with the law of conservation of mass.

A 27 g sample of an unknown hydrocarbon was burned in excess O_(2) to form 88g of CO_(2) and 27g of H_(2)O .What is possible molecular formula of hydrocarbon