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20.8 g of BaCl2 on reaction with 9.8 g o...

20.8 g of `BaCl_2` on reaction with 9.8 g of `H_2 SO_4` produces 7.3 g of HCl and some amount of `BaSO_4`. The amount of `BaSO_4` formed is

A

23.3 g

B

20.8 g

C

9.8 g

D

10.4 g

Text Solution

Verified by Experts

The correct Answer is:
A
According to law of conservation of mass,
Mass of reactants = Mass of products
`20.8 + 9.8 = 7.3 + ` mass of ` BaSO_4`
` therefore ` Mass of ` BaSO_4= 23.3 g`
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