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5.85 g of NaCl is dissolved in 1 L of pu...

5.85 g of NaCl is dissolved in 1 L of pure water. The number of ions in 1 mL of this solution is

A

`6.02 xx 10^(19)`

B

`1.2 xx 10^(22)`

C

`1.2 xx 10^(20)`

D

`6.02 xx 10^(20)`

Text Solution

Verified by Experts

The correct Answer is:
C
Number of molecules of NaCl in 1 L water
`= ( 5.85 )/( 58.5 ) xx 6.023 xx 10^(23) = 6.023 xx 10^(22) ` molecule
Number of molecules of NaCl in one ml solution
` = ( 6.023 xx 10^(22))/( 1000 ) = 6.023 xx 10^(19)`
` NaCl to Na^(+) +Cl^(-)`
one molecule gives 2 ions
` therefore ` Number of ions in one ml solution
`= 6.023 xx 10^(19) xx 2 = 1.2 xx 10^(20)`
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