Which of the following contains the greatest number of atoms?

Options

A. 1.0 g of butane `(C_4 H_(10))`
B. 1.0 g of nitrogen `(N_2)`
C. 1.0 g of silver (Ag)
D. 1.0 g of water `(H_2O)`

Answer

A

Explanation

Number of atoms = Number of molecules `xx` number of atoms in one molecule Number of atoms in 1.0 g butane `(C_4 H_(10))`
` = (1)/(58 ) xx 6.023 xx 10^(23) xx 14 = 1.45 xx 10^(23)`
(1 molecule contains 14 atoms)
Number of atoms in 1.0 g `N_2`
` = (1)/(28 ) xx 6.023 xx 10^(23) xx 2 =4.3 xx 10^(22)`
Number of atoms in 1.0 g silver (Ag)
`=(1)/(108 ) xx 6.023 xx 10^(23) = 5.5 xx 10^(21)`
Number of atoms in 1.0 g water (`H_2O `)
` =(1)/(18) xx 6.023 xx 10^(23) xx 3 ~~ 10^(23)`
Thus, butane has maximum number of atoms.