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A gas mixture contains 50% helium and 50...

A gas mixture contains 50% helium and 50% methane by volume. What is the percentage by weight of methane in the mixture?

A

`19.67%`

B

`20.05% `

C

`50%`

D

`80.03%`

Text Solution

Verified by Experts

The correct Answer is:
D
Equal volumes contain equal number of moles. Hence, molar ratio of He: `CH_4 =1:1`
` therefore ` Ratio by weight = 4:16 = 1:4
` therefore CH_4` present by weight `= 4/5 xx 100 = 80%`
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