The total number of electrons present in 18 mL of water (density of water is 1 g `mL^(-1)`) is

Options

A. `6.02 xx 10^(23)`
B. `6.02 xx 10^(22)`
C. `6.02 xx 10^(24)`
D. `6.02 xx 10^(25)`

Answer

C

Explanation

`18 mL H_2 O = 18 g H_2 O = 1 mol`
`= 6.02 xx 10^(23)` molecules
As there are ten electrons in `H_2O,` Avogadro.s number should be multiplied with 10.
`10 xx 6.02 xx 10^(23) e^(-) = 6.02 xx 10^(24) e^(-)`