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The empirical formula of an organic comp...

The empirical formula of an organic compound containing carbon and hydrogen is `CH_2` The mass of one litre of this organic gas is exactly equal to that of one litre of `N_2` Therefore, the molecular formula of the organic gas is

A

`C_2 H_4`

B

`C_3 H_6`

C

`C_6 H_(12)`

D

`C_4 H_8`

Text Solution

Verified by Experts

The correct Answer is:
A
Empirical formula weight` = 12 +2 xx 1 = 14` 22.4 L of` N_2 -= 28 g`
`implies 1L of N_2 = ( 28 )/(22.4 ) g`
Now ,1L or organic gas ` = ( 28 )/( 22.4 ) g `
` implies ` 22.4 L of orgainic gas ` = 28 g`
` therefore ` Molar weight of gas = 28 g
( Empirical weight)`""_(n)`, = Molecular weight
` n=( 28 )/(14)=2 `
Molecular formula =(Empirical formula)`""_(n), = (CH_2)_2 = C_2 H_4`
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