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50.0 kg of N(2(g)) and 10.0 kg of H(2(g)...

50.0 kg of `N_(2(g))` and 10.0 kg of `H_(2(g))` are mixed to produce `NH_(3(g))`. Identify the limiting reagent in the production of `NH_3` in this situation.

A

Nitrogen

B

Hydrogen

C

Can't be predicted

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
` underset(28 g) underset( 1 mol ) (N_2) + underset( 6g) underset(3mol ) (3H_2) to underset( 34 g) underset( 2 mol )(2NH_3)`
`( 50, 000 ) /( 28 ) =1785.7 mol , ( 10,000) /( 2) = 5,000 mol`
1 mol of `N_2` requires 3 mol of hydrogen
Thus, 1785.7 mol of `N_2` will need 5357.1 mol of `H_2`.
Thus, limiting reagent is `H_2`.
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