A metal M of equivalent mass E forms an oxide of molecular formula `M_x O_3` The atomic mass of the metal is given by the correct equation

Options

A. `2E(y//x)`
B. `xy//E`
C. `E//y`
D. `y//E`

Answer

A

Explanation

Let atomic mass of metal M be .a.
` therefore ` Mass of metal = ax , Mass of oxygen = 16 y
Equivalent mass of an element `= ( "Mass of element")/(" Mass of oxygen ") xx 8`
` therefore E = (a x )/( 16 Y) x x8 implies a = E ( 2y)/( x ) , i.e., a= 2E (y//x)`