10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be

Options

A. 3 mol
B. 4 mol
C. 1 mol
D. 2 mol

Answer

B

Explanation

` underset( 1 mol) underset(2 g) (H_2) + underset( 0.5 mol) underset( 16 g) ( 1//2 O_2) to underset( 1 mol) underset( 18 g) ( H_2 O)`
10 g of `H_2` = 5 mol and 64 g of `O_2` = 2 mol
` therefore ` In this reaction, oxygen is the limiting reagent so amount of `H_2 O` produced depends on that of `O_2`.
Since 0.5 mol of `O_2` gives 1 mol `H_2 O`
` therefore ` 2 mol of `O_2 ` will give 4 mol `H_2 O`.