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How many moles of ferric alum, (NH4)2 SO...

How many moles of ferric alum, `(NH_4)_2 SO_4 Fe_2(SO_4))3.24H_2O` can be made from the sample of Fe containing 0.0056 g of it?

A

`10^(-4) mol`

B

`0.5 xx 10^(-4) mol`

C

`0.33 xx 10^(-4) mol`

D

`2 xx 10^(-4)mol`

Text Solution

Verified by Experts

The correct Answer is:
B
`0.5 xx 10^(-4) mol`
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100 mL solution of ferric alum [Fe_(2)(SO_(4))_(3).(NH_(4))_(2)SO_(4).24H_(2)O (Mw=964g mol^(-1)) containing 2.41 g salt was boiled with Fe when the reaction Fe+Fe_(2)(SO_(4))_(3)to3FeSO_(4) Takes place. The unreacted iron was filtered off and the solution was titrated with (M)/(60)K_(2)Cr_(2)O_(7) in acidic medium. Q. Moles of FeSO_(4) formed when Fe reacts with Fe(2)(SO_(4))_(3) is

100 mL solution of ferric alum [Fe_(2)(SO_(4))_(3).(NH_(4))_(2)SO_(4).24H_(2)O (Mw=964g mol^(-1)) containing 2.41 g salt was boiled with Fe when the reaction Fe+Fe_(2)(SO_(4))_(3)to3FeSO_(4) Takes place. The unreacted iron was filtered off and the solution was titrated with (M)/(60)K_(2)Cr_(2)O_(7) in acidic medium. Q. Moles of FeSO_(4) formed when Cu reacts with Fe_(2)(SO_(4))_(3) is