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6.02 xx 10^(20) molecules of urea are pr...

`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of solution is

A

0.001 M

B

0.1 M

C

0.02 M

D

0.01 M

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of urea ` = ( 6.02xx 10^(20))/(6.02 xx 10^(23)) =0.001`
Concentration of solution` = ( 0.001 )/(100 ) xx 1000 =0.01 M`
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