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The higher oxide of an element (E) has t...

The higher oxide of an element (E) has the formula `EO_(3)` ,- Its hydride contains 2.47% hydrogen, the element is

A

Te

B

Se

C

S

D

Si

Text Solution

Verified by Experts

The correct Answer is:
B
Since the element (E) forms a higher oxide with the formula, `EO_(3)`, therefore, it must belong to group 16.
The hydrides of 16 group are `H_(2)S, H_(2)Te, H_(2)Se.`
% of hydrogen in `H_(2)S= (2)/(34) xx 100= 5.88`
% of hydrogen in `H_(2)Se = (2)/(81) xx 100= 2.47`
% of hydrogen in `H_(2)Te= (2)/(129.6) xx 100= 1.54`
As such Si which lies in group 14 and would form `SiO_(2)` as the higher oxide stands rejected.
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