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The pressure of a mixture of equal weigh...

The pressure of a mixture of equal weights of two gases of molecular weight 4 and 40, is 1.1 atm. The partial pressure of the lighter gas in this mixture is

A

0.55 atm

B

0.11 atm

C

1 atm

D

0.1 atm

Text Solution

Verified by Experts

The correct Answer is:
C
Let w g of each gas is taken ,
Mole freaction (x) of ligher gas = `((w)/(4))/((w)/(4) + (w)/(10)) = (10)/(11)`
Partial pressure of ligher gas = `P_("total") xx ` mole fraction
` = 1.1 xx (10)/(11) = 1` atm
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