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Pressure of a mixture of 4 g of O2 and 2...

Pressure of a mixture of 4 g of `O_2` and 2 g of `_2`, confined in a bulb of 1 L at `0^(@)C` is

A

25.215 atm

B

31.205 atm

C

45.215 atm

D

15.210 atm.

Text Solution

Verified by Experts

The correct Answer is:
A
Applying , `PV = (w)/(M) RT` to both the gases separately ,
`P_(O_2) = (4)/(32) xx (0.0821 xx 273)/(1) = 2.81 ` atm
` P_(H_2) = (2)/(2) xx (0.0821 xx 273)/(1) = 22.4 ` atm
Now , according to Dalton .s law ,
`P_("Total") = P_(O_2) + P_(H_2)` = 2.81 = 22.4 = 25.21 atm
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