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A 1:1 mixture (by weight) of hydrogen an...

A 1:1 mixture (by weight) of hydrogen and helium is enclosed in a one litre flask kept at `0^(@)C`. Assuming ideal behaviour, the partial pressure of helium is found to be 0.42 atm. Then the concentration of hydrogen would be

A

0.0375 M

B

0.028 M

C

0.0562 M

D

0.0187 M

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(He)= x_(He) xx P_("total")`
i.e., `0.42 = (w//4)/((w//4) + (w//2)) xx P_("total")`
or `P_("total") = 1.26 atm `
`:. P_(H_2) = 1.26 - 0.42 = 0.84` atm
`:. ` Molar conc. (C) = `(P)/(RT) = (0.84)/(0.0821 xx 273) = 0.0375`M
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