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There is a mixture of H2 and He which co...

There is a mixture of `H_2` and He which contains 40% by mass of `H_2`. Calculate the fraction of total pressure exerted by `H_2`

A

`4//7`

B

`3//7`

C

`4//9`

D

`5//9`

Text Solution

Verified by Experts

The correct Answer is:
A

Let the total mass of gases be 100 g
Mass of `H_2 = 40`g , Moles of `H_2 = (40)/(2) = 20`
Mass of He = 60 g , Moles of He `=(60)/(4) = 15`
Mole fraction of `H_2= (20)/(15 + 20) =(20)/(35) = (4)/(7)`
`4//7` is the fraction of pressure exerted by `H_2` .
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