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A 0.5 dm^(3) flask contains gas A and 1 ...

A 0.5 `dm^(3)` flask contains gas A and 1 `dm^(3)` flask contains gas B at the same temperature. If density of A = 3.0 g `dm^(-3)` and that of B= 1.5 g `dm^(-3)` and the molar mass of `A=(1)/(2)` of B, then the ratio of pressure exerted by gases is

A

`P_(A) // P_(B) =2`

B

`P_(A) // P_(B) = 1`

C

`P_(A) // P_(B) = 4`

D

`P_(A) // P_(B) = 3 `

Text Solution

Verified by Experts

The correct Answer is:
C
`P= d(RT)/(M)` , at constant T
`(P_A)/(P_B) = (d_A)/(d_B) (M_B)/(M_A) = (3.0)/(1.5) xx 2 = 4`
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