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At high pressure, the compressibility fa...

At high pressure, the compressibility factor Z is equal to

A

unity

B

`1-(Pb)/(RT)`

C

`1+(Pb)/(RT)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
C
`(P+(a)/(V^(2))) (V-b) = RT`
At high pressure b cannot be neglected in comparison to V .
Further though V becomes small `a//V^(2)` is large but as P is very high ,`a//V^(2)` can be neglected in comparison to P. Hence
`P(V-b) =RT or PV = RT + Pb`
`or (PV)/(RT) =1 + (Pb)/(RT) i.e. Z = 1 + (Pb)/(RT)`
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