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203. Surface tension of water at 25^(@)C...

203. Surface tension of water at `25^(@)C` is `7.2 xx 10^(-2) Nm^(-1)`. In order to increase surface area of water by 100 `cm^(2)`, the amount of work done will be

A

`7.2 xx 10^(-4)J`

B

`7.2J`

C

72J

D

0.72J

Text Solution

Verified by Experts

The correct Answer is:
A
Work done = surface energy `xx` increase in surface area
`= 7.2 xx 10^(-2) xx (100 xx 10^(-4) m^(2)) = 7.2 xx 10^(-4) J`
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