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The pressure exerted by 6.0 g of methane...

The pressure exerted by 6.0 g of methane gas in a 0.03 `m^3` vessel at `129^(@)C` is (Atomic masses: C= 12.01, H = 1.0.1 and R= 8.314 j `K^-1 mol^-1`)

A

215216 Pa

B

13409 Pa

C

41648 Pa

D

31684 Pa

Text Solution

Verified by Experts

The correct Answer is:
C
Given, mass of `CH_4`, w= 6g
volume of `CH_4`, V = 0.03 `m^3`
`T = 129^(@)C` = 129 + 273 = 402 K
R = 8.314 `J K^-1 mol^-1`
Molecular mass of `CH_4` M= 12.01+4 x 1.01 = 16.05
`PV= nRT=W/M RT`
`PV= nRT = (W)/(M) RT`
`:. P= (W)/(M) (RT)/(V) = (6)/(16.05) xx (8.314 xx 402)/(0.03) = 41647.7 Pa ~~ 41648 Pa`
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