Home
Class 11
CHEMISTRY
One mole of a symmetrical alkene on ozon...

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is

A

ethene

B

propene

C

1-butene

D

2-butene.

Text Solution

Verified by Experts

The correct Answer is:
D
`underset"(Symm. alkene)"(RCH=CHR) underset((ii)Zn,H_2O)overset((i)O_3)to2RCHO`
Molecular mass of RCHO=44
`rArr` R+12+1+16=44
Mol. Mass of R = 44-29 = 15
This is possible , only when R is -`CH_3` group.
The aldehyde is `CH_3CHO` and the symmetrical alkene is `CH_3CH=CHCH_3`
`underset"2-Butene"(CH_3CH=CHCH_3) underset((ii)Zn,H_2O)overset((i)O_3)tounderset"Acetaldehyde"(2CH_3CHO)`
Promotional Banner

Similar Questions

Explore conceptually related problems

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44u. The alkene is:

One mole of symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass 58 . The alkene

One mole of symmetrical alkene upon ozonolysis gives two moles of an aldehyde having the molecular mass 44 u . Predict the alkene.

One mole of alkene an ozonolysis gives two moles of butanone. The alkene is :

One mole of alkene on ozonolysis gives 2 moles of butanone. The alkene is:

Unbranched alkenes on ozonolysis give -