Iron crystallizes in a bcc system with a lattice parameter of 2.861 Å. Calculate the density of iron in the boc system.
(Given : atomic weight of `Fe = 56, N_0=6.023 xx 10^(23)mol^(-1)`.)

Explanation

Density, `rho = (ZxxM)/(N_0xxa^3), For bcc, Z=2`
`rho_(Fe) = (2 xx 56.0)/(6.023xx10^(23)xx (2.861xx10^(-8))^3) = 7.94 g cm^(-3)`