The oxidation state of sulphur in the anions `SO_(3)^(2-) , S_2O_(4)^(2-)` and `S_2O_(6)^(2-)` follows the order

Options

A. `S_2O_(6)^(2-) lt S_2O_(4)^(2) lt SO_(3)^(2-)`
B. `S_(2)O_(6)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`
C. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_2O_(6)^(2-)`
D. `S_(2)O_(4)^(2-) lt S_2O_6^(2-) lt SO_(3)^(2-)`

Answer

B

Explanation

`SO_(3)^(2) rArr x + 3 (-2) = -2 rArr x = +4`
`S_2O_(4)^(2-) rArr 2x + 4(-2) = - 2 rArr 2x = + 6 rArr x = +3`
`S_2O_(6)^(2) rArr 2x + 6(-2) = -2 rArr 2x = + 10 rArr x = + 5`
Thus, increasing order of oxidation state is
`S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`