Pick out the correct statement with respect to `[Mn(CN)_6]^(3-)`

Options

A. It is `sp^3 d^2` hybridised and tetrahedral.
B. It is `d^2sp^3` hybridised and octahedral.
C. It is `dsp^2` hybridised and square planar.
D. It is `sp^3d^2` hybridised and octahedral.

Answer

B

Explanation

`[Mn(CN)_6]^(3-)`
Let oxidation state of Mn be x.
x+6 x (-1)=-3
x = +3
Electronic configuration of `Mn: [Ar]4s^2 3d^5`
Electronic configuration of `Mn^(3+): [Ar]3d^4`
` CN^-` is a strong field ligand thus, it causes pairing of electrons in 3d-orbital.

Then, `[Mn(CN)_6]^(3-)` has `d^2sp^3` hybridisation and has octahedral geometry.