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A current I flows through a closed loop ...

A current I flows through a closed loop as shown in figure. The magnetic field induction at the centre 0 is

A

`(mu_(0)I)/(4piR)theta`

B

`(mu_(0)I)/(4piR)(theta+sintheta)`

C

`(mu_(0)I)/(4piR)(pi-theta+sintheta)`

D

`(mu_(0)I)/(4piR)(pi-theta+tantheta)`

Text Solution

Verified by Experts

The correct Answer is:
D
`B_(O)=B_(pqs)+B_(sp)`
`=(mu_(0))/(4pi)(I)/(R)(2pi-2theta)+(mu_(0))/(4pi)(I)/(Rcostheta)(sintheta+sintheta)`
`=(mu_(0))/(2pi)[pi-theta+tantheta]`
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