A charged particle is moving in a circular orbit of radius 6 cm with a uniform speed of `3 xx 10^(6) m//s` under the action of a uniform magnetic field `2 xx 10^(-4) Wb"/"m^(2)` at right angles to the plane of the orbit. The charge to mass ratio of the particle is

Options

A. `5xx10^(-9)C"/"kg`
B. `2.5xx10^(11)C"/"kg`
C. `5xx10^(11)C"/"kg`
D. `5xx10^(12)C"/"kg`

Answer

B

Explanation

Here , v=`3xx10^(6)ms^(-1)`
`B=2xx10^(-4)Wbm^(-1)=2xx10^(-4)T`
`R=6cm=6xx10^(-2)m`
AS `Bqv=(mv^(2))/(R)or(q)/(m)=(v)/(BR)`
Substituting the given values , we get
`(q)/(m)=(3xx10^(6))/(2xx10^(-4)xx6xx10^(-2))=0.25xx10^(12)C"/"kg`
`2.5xx10^(11)C"/"kg`