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A straight horizontal conducting rod of length 50 cm and mass 50 g is suspended by two vertical wires at its ends. A current of 5.0 A is set up in the rod through the wires. What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero? `(take=10ms_(-2)`

A

0.05T

B

0.1T

C

0.2T

D

0.5T

Text Solution

Verified by Experts

The correct Answer is:
C
Here `l=50cm=50xx10^(-2)m`
`m=50 g=50xx10^(-3)kg,I=5.0A`
Tension in the wire is zero if the force on the road due to magnetic dield is equal and opposite to the weight of the road.
I.e, mg=Bllor B`=(mg)/(ll)`
Substituting the given values , we get
`B=(50xx10^(-3)xx10)/(5xx50xx10^(-2))=0.2T`
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