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A square loop of side 15 cm carrying a ...

A square loop of side 15 cm carrying a steady current of 5 A is placed with its one side parallel to a long straight conductor carrying a current of 10A as shown in figure. The correct statement related to net force experienced by the loop due to wire is (a) repulsive in nature having magnitude equal to

A

repusive in nature having magnitude equal to `3.37xx10^(-5)N`

B

repusive in nature having magnitude equal to`2.25xx10^(-5)N`

C

attractivein nature having magnitude equal to`2.25xx10^(-5)N`

D

attractivein nature having magnitude equal to`2.25xx10^(-5)N`

Text Solution

Verified by Experts

The correct Answer is:
C
Force experienced by AB and CD are equal and opposite so the contribution in the net force experienced by loop is only due to AD and BC.
Magnetic field at the location of AD is `B_(1)=(mu_(0)I_(1))/(2pi(5xx10^(-2)m))=(2xx10^(-7)xx10)/(5xx10^(-2))ox`
`4xx10^(-5)Tox` ,br> Magnetic force experienced by AD is
`F_(1)=I_(2)B_(1)xx(15xx10^(-2)m)=3xx10^(-5)`Ntoward wire.
Magnetic field at the location of BC is `B_(1)=(mu_(0)I_(1))/(2pi(20 cm))=(2xx10^(-7)xx10)/(20xx10^(-2))1xx10^(-5)Tox`
Magnetic force experienced by BC is ,
`F_(2)=L_(2)B_(2)xx(15cm)=0.75xx10^(-5)`N away from wire .
Net force experienced by loop is `F=(F_(1)-F_(2))` toward wire =`2.25xx10^(-5)` N toward the wire.
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Knowledge Check

  • A square loop ABCD carrying a current i is placed near and coplanar with a long straight conductor XY carrying a current I .

    A
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    B
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    `(mu_(0) I_(1) I_(2))/(2pi)`
    B
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