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A galvanometer of resistance 20 W gives ...

A galvanometer of resistance 20 W gives a full scale deflection when a current of 0.04 A is passed through it. It is desired to convert it into an ammeter of range 20 A. The only shunt available is 0.05 W. The resistance that must be connected in series with the coil of the galvanometer IS

A

4.95`Omega`

B

5.94`Omega`

C

9.45`Omega`

D

12,62`Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
Let R be resistance connected in series with the galvameter .
From figure
`(I_(g))/(I-I_(g))=(S)/(G+R)`
`R=S((I)/(I_(g))-1)-G`
Substituting the given values, we get
`R=0.05((20)/(0.04)-1)-20=4.95Omega`
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MTG GUIDE-MAGNETIC EFFECTS OF CURRENT AND MAGNETISM-NEET CAFE (TOPICWISE PRACTICE QUESTIONS)(MOVING COIL GALVANOMETER)
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