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A galvanometer of resistance G can measu...

A galvanometer of resistance G can measure 1 A curent. If a shunt Sis used to convert it into an ammeter to measure
10A current. The ration of `(G)/(S)` is

A

`(1)/(9)`

B

`(9)/(1)`

C

10

D

`(1)/(10)`

Text Solution

Verified by Experts

The correct Answer is:
B
Here `I_(g)=1A`
I=10A
From figure
`I_(g)G=(I-I_(g))S`
`(G)/(S)=(I-I_(g))/(I_(g))`
Substituting the given values we get `(G)/(S)=(10A-1A)/(1A)=(9)/(1)`
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