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A bar magnet has a magnetic moment 2.5 J...

A bar magnet has a magnetic moment 2.5 J`T^(-4)`- and is placed in a magnetic field of 0.2 T. The work done in turning the magnet from parallel to antiparallel position relative to field direction is

A

1J

B

2J

C

3J

D

4J

Text Solution

Verified by Experts

The correct Answer is:
A
Work done is changing the oriention of dipole of moment M is a magnetic field B from position `theta_1 " to " theta_2` is given by
`W = MB(cos theta_1 - cos theta_2)`
Here, `theta_1 = 0^@` and `theta_2 = 180^@`
So, `W = 2 MB= 2 xx 2.5 xx 0.2 = 1 J`
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