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A magnet of magnetic moment of 50 hat i ...

A magnet of magnetic moment of 50 `hat i A m^2` is placed along the x - axis in magnetic field `vec B = (0.5 hat i + 3.0 hat j)T.` The torque acting on the manet is

A

` 175 hat k` Nm,

B

`75 hat i Nm`

C

`150 hat i Nm`

D

`25 sqrt(37) hat i Nm,`

Text Solution

Verified by Experts

The correct Answer is:
C
Torque ` vec tau = vec M xx vec B`
Therefore, `vec tau = 50 i xx (0.5 hat i + 3.0 hat j)`
Since `hat i xx hat i = 0 and hat i xx hat j = hat k therefore vec tau = 150 hat k Nm `
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