A magnetising field of 1600 A `m^(-1)` produces a magnetic flux of `2.4 xx 10^(-5)` Wb in an iron bar of cross-sectional area 0.2 c`m^(2)`. The susceptibility of an iron bar is

Options

A. 298
B. 596
C. 1192
D. 1788

Answer

B

Explanation

Here Magnetic field H=1600 `Am^(-1)`
Magnetic flux , `phi=2.4xx10^(-5)`Wb
Area, A=0.2 `cm^(-2)=0.2xx10^(-4)m^(-2)`
`:. B=(phi)/(A)(2.4xx10^(-5)Wb)/(0.2xx10^(-4)m^(2))=1.2Wbm^(-2)`
Magnetic pereability ,`mu=(B)/(H)`
`=(1.2Wbm^(-2))/(1600Am^(-1))=7.5xx10^(-4)WbA^(-1)m^(-1)`
Magnetic susceptibility , `chi=(mu)/(mu_(0))-1`
`= ((7.5xx10^(-4)WbA^(-1)m^(-1)))/((4pixx10^(-4)WbA^(-1)m^(-1)))=1=596`