The value of x+y+z is `15` if a,x,y,z,b are in AP while `1/x+1/y+1/z` is `5/3` if a,x,y,z,b are in HP ,then the value of a is

Given that x+y+z =15 when a,x,y,z,b are in A.P and 1/x+1/y+1/z=5/3 when a,x,y,z,b are in H.P .Then

x+y+z=15 if 9, x, y, z, a are in A.P. while (1)/(X)+(1)/(Y)+(1)/(Z)=(5)/(3)if9,X, Y, Z, a are in H.P., then the value of a will be -

(i) The value of x + y + z is 15. If a, x, y, z, b are in AP while the value of (1)/(x) + (1)/(y) + (1)/(z) " is " (5)/(3) . If a, x, y, z b are in HP, then find a and b (ii) If x,y,z are in HP, then show that log (x +z) + log (x +z -2y) = 2 log ( x -z) .

If a,x,b are in H.P. And a,y,z,b are in G.P.,then the value of (yz)/(x(y^3+z^3)) is

If a, x, y, z, b are in A.P., then value of xyz is 35/3 and if a, x, y, z, b are in H.P., then value of xyz is 75/7, where a and b are given positive integers. Then value of (ab) is

If a,x,y,z,b are in AP then x+y+z=15 and if a,x,y,z,b are in HP.then (1)/(x)+(1)/(y)+(1)/(z)=(5)/(3). Numbers a,b are

If x, y, z are in H.P., then the value of (x+y)/(y-x)+(y+z)/(y-z) is