Let `f : R -> R` be defined as `f(x) = x^3 + 3x^2 + 6x-5 + 4e^(2x) and g(x)= f^-1(x)`, then find `g' (-1)`.

Let f:R rarr R be defined as f(x)=x^(3)+3x^(2)+6x-5+4e^(2x) and g(x)=f^(-1)(x) ,then find g'(-1)

Let f : R to R be defined by f(x) = x^(3) + x^(2) + 5x + 2 sin x , Then

Let f:R rarr R be defined as f(x)=(2x-3 pi)^(2)+(4)/(3)x+cos x and g(x)=f'(x) , then find g(x)

Let f:RtoR be defined as f(x)=(2x-3pi)^(3)+(4)/(3)x+cosx and g(x)=f^(-1)(x) then

Let f:R rarr R defined by f(x)=x^(3)+e^((x/2)) and let g(x)=f^(-1)(x) then the value of g'(1) is

Let f:R rarr R defined by f(x)=x^(3)+e^(x/2) and let g(x)=f^(-1)(x) then the value of g'(1) is

Let f:R to R be defined by f(x)=3x-4. Then, f^(-1) (x) is

Let f :R to R be fefined as f(x) = 2x -1 and g : R - {1} to R be defined as g(x) = (x-1/2)/(x-1) Then the composition function ƒ(g(x)) is :

Let f: R to R be defined by f(x) = 5^(2x)/(5^(2x) + 5) , then f(x) + f(1-x) is equal to